7x^2+20x=350

Solution for 7x^2+20x=350 equation:

7x^2+20x=350

We move all terms to the left:

7x^2+20x-(350)=0

a = 7; b = 20; c = -350;
Δ = b2-4ac
Δ = 202-4·7·(-350)
Δ = 10200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10200}=\sqrt{100*102}=\sqrt{100}*\sqrt{102}=10\sqrt{102}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{102}}{2*7}=\frac{-20-10\sqrt{102}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{102}}{2*7}=\frac{-20+10\sqrt{102}}{14}
$